Proof of Bertrand's Postulate
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High Quality Content by WIKIPEDIA articles! In mathematics, Bertrand's postulate (actually a theorem) states that for each n ¿ 2 there is a prime p such that n < p < 2n. It was first proven by Pafnuty Chebyshev, and a short but advanced proof was given by Srinivasa Ramanujan. The gist of the following elementary but involved proof by contradiction is due to Paul Erd¿s; the basic idea of the proof is to show that a certain binomial coefficient needs to have a prime factor within the desired interval in order to be large enough.
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High Quality Content by WIKIPEDIA articles! In mathematics, Bertrand's postulate (actually a theorem) states that for each n ¿ 2 there is a prime p such that n < p < 2n. It was first proven by Pafnuty Chebyshev, and a short but advanced proof was given by Srinivasa Ramanujan. The gist of the following elementary but involved proof by contradiction is due to Paul Erd¿s; the basic idea of the proof is to show that a certain binomial coefficient needs to have a prime factor within the desired interval in order to be large enough.
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High Quality Content by WIKIPEDIA articles! In mathematics, Bertrand's postulate (actually a theorem) states that for each n ¿ 2 there is a prime p such that n < p < 2n. It was first proven by Pafnuty Chebyshev, and a short but advanced proof was given by Srinivasa Ramanujan. The gist of the following elementary but involved proof by contradiction is due to Paul Erd¿s; the basic idea of the proof is to show that a certain binomial coefficient needs to have a prime factor within the desired interval in order to be large enough.
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